About the operation of [to return]

Hi,

We know [return evil for good = return good with evil] .

I want to learn how all roads lead to Rome in that way.

Let me try give the reason for why.

1. [return evil for good] = does evil that is in exhange for good ; or evil in return for good;

the logic position :

in return

good ---------------

return or for good

evil does evil

2. [return good with evil] = in exchange for good, return a thing or action which is with evil / goes with evil / attends on evil;

in exchang

=

for good

-------------------

return a thing or action

------------------------

which

attends

on evil

Above two instances we can find its logic orders are the same way with each other.

So, they are equal to each other.

Could any one correct it for me ?

Thank you for your assistance.